If two actuating cylinders have the same cross-sectional area but different lengths of stroke, what will they exert when connected to the same hydraulic pressure source?

The correct answer is that the two actuating cylinders will exert equal amounts of force and will move at the same rate of speed. This is because the force exerted by a hydraulic cylinder is determined by the hydraulic pressure applied and the cross-sectional area of the piston. Since both cylinders have the same cross-sectional area and are connected to the same hydraulic pressure source, they will generate the same force.

However, the rate of speed at which they move is influenced by additional factors, such as the flow rate of the hydraulic fluid supplied to each cylinder. If both cylinders receive the same flow rate and have identical cross-sectional areas, they will also move at the same speed, irrespective of their stroke lengths. The length of the stroke does not affect the force exerted or the speed of movement under these conditions—the movement information reflects the distance traveled rather than the rate of speed per unit of input volume of fluid.

Thus, the fundamental relationship of pressure, area, and force leads to the conclusion that both cylinders will perform equally regarding force output and movement speed under the specified conditions.